Java Integer compareTo() method. but if you want to use compareTo just create a Double array. In order to sort a collection of objects (using some property) in Java, we can use the java.lang.Comparable interface which imposes a natural ordering on the objects of each class that implements it. Java Boolean compareTo() method. Working on a sorted list I came to a point I needed to implement a compareTo() function for primitive long values. ... public int compareTo( NumberSubClass referenceName ) Parameters. Arrays.sort(array) This tutorial shows various examples of sorting an array using such methods, especially using the Comparable and Comparator interfaces. How to Compare Two Objects in Java? It returns the result of the value 0 if Integer is equal to the argument Integer, a value less than 0 if Integer is less than the argument Integer and a value greater than 0 if Integer is greater than the argument Integer. The compareTo() method returns an int that is negative if a b. I'm not looking for the obvious naive implementation, but was wondering if there's an elegant one-liner code to do that (without creating a new Long(value)).. Maybe something like this: compareTo is a method of a class. Primitive data types aren't classes and have no methods you can call. I will explain both methods using Strings and a self-written “Student” class as examples. We assume that compareTo() method has been added to the class. using the operators <, <=, ==, =>, >.That does not work for objects. For objects, you either use a compare or a compareTo method instead. 二. Comparable接口中的compareTo compareTo方法内必须做非空判断（规范问题），当然int类型就不用了。 注意事项： 1、模型必须实现Comparable接口 2、Collection.sort(list)会自动调用compareTo,如果没有这句，list是不会排序的，也不会调用compareTo方法 [TODO: Add explanation and example] a.compareTo(b) N/A : Comparable interface. It is possible to compare Byte, Long, Integer, etc. In this post, we will see how to sort a List of objects using Comparable in Java. The compareTo() method is a method of Integer class under java.lang package.This method compares two integer objects numerically. You compare Java primitives (int, long, double, etc.) The compareTo() method of Integer class of java.lang package compares two Integer objects numerically and returns the value 0 if this Integer is equal to the argument Integer; a value less than 0 if this Integer is numerically less than the argument Integer; and a value greater than 0 if this Integer is numerically greater than the argument Integer (signed comparison). Java - compareTo() Method - The method compares the Number object that invoked the method to the argument. You have to encapsulate your int in an instance of the class java.lang.Integer This tutorial helps you how to use the Arrays utility class to sort elements in an array.. You know, the java.util.Arrays class provides various methods for sorting elements of an array, as simple as:. This lets you keep your doubles in an array of primitives, and avoid autoboxing before calling an instance method. Here is the simplest example of autoboxing: 回答2: for primitive types do not use compareTo, use == instead. The compareTo() method of Java Boolean class compares the Boolean instance with the Boolean argument and returns … The best treatment of the issues is in Horstmann's Core Java Vol 1. Compares values and returns an int which tells if the values compare less than, equal, or greater than. For example, converting an int to an Integer, a double to a Double, and so on.If the conversion goes the other way, this is called unboxing.. Double[] dist = new Double[centroids.size()]; 回答3: In java primitive types don't have any methods. Autoboxing is the automatic conversion that the Java compiler makes between the primitive types and their corresponding object wrapper classes. It returns 0 if a equals b, and it returns a positive int if a > b. Here is an example involving Fraction objects.